作业帮计算（2X^2Y-2XY^2)-[(-3X^2Y^2+3X^2Y)+(3X^2Y^2-3XY^2)]X=-1 Y=2
来源：学生作业帮助网 编辑：作业帮 时间：2024/08/11 00:19:05
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计算（2X^2Y-2XY^2)-[(-3X^2Y^2+3X^2Y)+(3X^2Y^2-3XY^2)]X=-1 Y=2
计算（2X^2Y-2XY^2)-[(-3X^2Y^2+3X^2Y)+(3X^2Y^2-3XY^2)]
X=-1 Y=2
计算（2X^2Y-2XY^2)-[(-3X^2Y^2+3X^2Y)+(3X^2Y^2-3XY^2)]X=-1 Y=2
解
（2X^2Y-2XY^2)-[(-3X^2Y^2+3X^2Y)+(3X^2Y^2-3XY^2)]
=(2x^2y-2xy^2)-(3x^2y-3xy^2)
=(2x^2y-3x^2y)+(-2xy^2+3xy^2)
=-x^2y+xy^2
=-xy(x-y)
=-2(-1-2)
=6
