计算:(5xy^2(x^2-3xy)-(-3x^2y)^2)/2x^2y^2

来源:学生作业帮助网 编辑:作业帮 时间:2024/07/17 22:43:09
计算:(5xy^2(x^2-3xy)-(-3x^2y)^2)/2x^2y^2
x){nuaZQgQgk\Q*54@8#"}4ِaG4n( mM+⌁<]CSeEI%:2 \9\ UiiH~qAb[6`󞯝l ׽b뼧z-dGr

计算:(5xy^2(x^2-3xy)-(-3x^2y)^2)/2x^2y^2
计算:(5xy^2(x^2-3xy)-(-3x^2y)^2)/2x^2y^2

计算:(5xy^2(x^2-3xy)-(-3x^2y)^2)/2x^2y^2
[(5xy^2(x^2-3xy)-(-3x^2y)^2]/2x^2y^2
=[5x^3y^2-15x^2y^3-9x^4y^2]/2x^2y^2
=5x^3y^2/2x^2y^2-15x^2y^3/2x^2y^2-9x^4y^2/2x^2y^2
=2.5x-7.5y-4.5x^2

回答正确,赞同楼上