如图,在△ABC中,AD是∠BAC的平分线,M是BC的中点,过点M作ME//AD交BA的延长线于点E,交AC于点F.求证:BE=CF=1/2(AB+AC)
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![如图,在△ABC中,AD是∠BAC的平分线,M是BC的中点,过点M作ME//AD交BA的延长线于点E,交AC于点F.求证:BE=CF=1/2(AB+AC)](/uploads/image/z/6646149-45-9.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E2%96%B3ABC%E4%B8%AD%2CAD%E6%98%AF%E2%88%A0BAC%E7%9A%84%E5%B9%B3%E5%88%86%E7%BA%BF%2CM%E6%98%AFBC%E7%9A%84%E4%B8%AD%E7%82%B9%2C%E8%BF%87%E7%82%B9M%E4%BD%9CME%2F%2FAD%E4%BA%A4BA%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%BA%8E%E7%82%B9E%2C%E4%BA%A4AC%E4%BA%8E%E7%82%B9F.%E6%B1%82%E8%AF%81%EF%BC%9ABE%3DCF%3D1%2F2%EF%BC%88AB%2BAC%EF%BC%89)
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