如图,在△ABC中,AD平分∠BAC,G为BC中点,EG平行AD交AC于F,交BA延长线于E.求证:CF=1/2(AB+AC)如图,在△ABC中,AD平分∠BAC,G为BC中点,EG平行AD交AC于F,交BA延长线于E.求证:CF=1/2(AB+AC)
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![如图,在△ABC中,AD平分∠BAC,G为BC中点,EG平行AD交AC于F,交BA延长线于E.求证:CF=1/2(AB+AC)如图,在△ABC中,AD平分∠BAC,G为BC中点,EG平行AD交AC于F,交BA延长线于E.求证:CF=1/2(AB+AC)](/uploads/image/z/6646150-46-0.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E2%96%B3ABC%E4%B8%AD%2CAD%E5%B9%B3%E5%88%86%E2%88%A0BAC%2CG%E4%B8%BABC%E4%B8%AD%E7%82%B9%2CEG%E5%B9%B3%E8%A1%8CAD%E4%BA%A4AC%E4%BA%8EF%2C%E4%BA%A4BA%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%BA%8EE.%E6%B1%82%E8%AF%81%EF%BC%9ACF%3D1%2F2%28AB%2BAC%29%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E2%96%B3ABC%E4%B8%AD%2CAD%E5%B9%B3%E5%88%86%E2%88%A0BAC%2CG%E4%B8%BABC%E4%B8%AD%E7%82%B9%2CEG%E5%B9%B3%E8%A1%8CAD%E4%BA%A4AC%E4%BA%8EF%2C%E4%BA%A4BA%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%BA%8EE.%E6%B1%82%E8%AF%81%EF%BC%9ACF%3D1%2F2%28AB%2BAC%29)
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