化简(3/x-1-x-1)÷x-2/x的平方-2x+1
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化简(3/x-1-x-1)÷x-2/x的平方-2x+1
化简(3/x-1-x-1)÷x-2/x的平方-2x+1
化简(3/x-1-x-1)÷x-2/x的平方-2x+1
是不是
[3/(x-1)-x-1]÷[(x-2)/(x²-2x+1)]
[3/(x-1)-x-1]÷[(x-2)/(x²-2x+1)]
={[3-(x²-1)]/(x-1)}÷[(x-2)/(x-1)²]
=[(4-x²)/(x-1)]÷[(x-2)/(x-1)²]
=(-2-x)(x-1)
=-x²-x+1
这是错的!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!11
[3/(x-1)-x-1]/[(x-2)/(x^2-2x+1)]
=(4-x^2)/(x-1)*(x-1)^2/(x-2)
=-x-2