求123...n...321(1+2+3+...+n+...+3+2+1)的算术平方根
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![求123...n...321(1+2+3+...+n+...+3+2+1)的算术平方根](/uploads/image/z/6703923-3-3.jpg?t=%E6%B1%82123...n...321%281%2B2%2B3%2B...%2Bn%2B...%2B3%2B2%2B1%29%E7%9A%84%E7%AE%97%E6%9C%AF%E5%B9%B3%E6%96%B9%E6%A0%B9)
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求123...n...321(1+2+3+...+n+...+3+2+1)的算术平方根
求123...n...321(1+2+3+...+n+...+3+2+1)的算术平方根
求123...n...321(1+2+3+...+n+...+3+2+1)的算术平方根
(1+2+3+...+n+...+3+2+1)
=n*(n+1)/2+n(n-1)/2
=n/2*2n
=n^2
所以,原式的算术平方根就是n