已知函数f(x)=3ax+1-2a,在[-1,1]上存在x1,使f(x1)=0(x1不等于正负一),则a的取值范围是( )A.(-1,1/5)B.(1/5,+∞)C.(-∞,-1)∪(1/5,+∞)D.(-∞,-1)
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![已知函数f(x)=3ax+1-2a,在[-1,1]上存在x1,使f(x1)=0(x1不等于正负一),则a的取值范围是( )A.(-1,1/5)B.(1/5,+∞)C.(-∞,-1)∪(1/5,+∞)D.(-∞,-1)](/uploads/image/z/671014-46-4.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%3D3ax%2B1-2a%2C%E5%9C%A8%5B-1%2C1%5D%E4%B8%8A%E5%AD%98%E5%9C%A8x1%2C%E4%BD%BFf%28x1%29%3D0%28x1%E4%B8%8D%E7%AD%89%E4%BA%8E%E6%AD%A3%E8%B4%9F%E4%B8%80%29%2C%E5%88%99a%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%E6%98%AF%EF%BC%88+%EF%BC%89A.%EF%BC%88-1%2C1%2F5%EF%BC%89B.%EF%BC%881%2F5%2C%2B%E2%88%9E%EF%BC%89C.%EF%BC%88-%E2%88%9E%2C-1%EF%BC%89%E2%88%AA%EF%BC%881%2F5%2C%2B%E2%88%9E%EF%BC%89D.%EF%BC%88-%E2%88%9E%2C-1%EF%BC%89)
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