已知**A={(x,y)|ax+y=1},B={(x,y)|x+ay=1},C={(x,y)|x²+y²=1}则(1)a为何值时(A∪B)∩C是2元集(2)a为何值时(A∪B)∩C是3元集答案是(1)a=0或1 (2)a=-1±√2,还有我只是一高一新生,
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![已知**A={(x,y)|ax+y=1},B={(x,y)|x+ay=1},C={(x,y)|x²+y²=1}则(1)a为何值时(A∪B)∩C是2元集(2)a为何值时(A∪B)∩C是3元集答案是(1)a=0或1 (2)a=-1±√2,还有我只是一高一新生,](/uploads/image/z/6715309-13-9.jpg?t=%E5%B7%B2%E7%9F%A5%2A%2AA%3D%7B%28x%2Cy%29%7Cax%2By%3D1%7D%2CB%3D%7B%28x%2Cy%29%7Cx%2Bay%3D1%7D%2CC%3D%7B%28x%2Cy%29%7Cx%26%23178%3B%2By%26%23178%3B%3D1%7D%E5%88%99%EF%BC%881%EF%BC%89a%E4%B8%BA%E4%BD%95%E5%80%BC%E6%97%B6%EF%BC%88A%E2%88%AAB%EF%BC%89%E2%88%A9C%E6%98%AF2%E5%85%83%E9%9B%86%EF%BC%882%EF%BC%89a%E4%B8%BA%E4%BD%95%E5%80%BC%E6%97%B6%EF%BC%88A%E2%88%AAB%EF%BC%89%E2%88%A9C%E6%98%AF3%E5%85%83%E9%9B%86%E7%AD%94%E6%A1%88%E6%98%AF%EF%BC%881%EF%BC%89a%3D0%E6%88%961+%EF%BC%882%EF%BC%89a%3D-1%C2%B1%E2%88%9A2%2C%E8%BF%98%E6%9C%89%E6%88%91%E5%8F%AA%E6%98%AF%E4%B8%80%E9%AB%98%E4%B8%80%E6%96%B0%E7%94%9F%2C)
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