计算 1/(m²-m)+(m-5)/(2m²-2)=?

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/25 20:47:41
计算 1/(m²-m)+(m-5)/(2m²-2)=?
x){nu US64}S5@2F0)#MR>: l(P_#7H7WS[PS_5K aFچ`

计算 1/(m²-m)+(m-5)/(2m²-2)=?
计算 1/(m²-m)+(m-5)/(2m²-2)=?

计算 1/(m²-m)+(m-5)/(2m²-2)=?
1/(m^2-m)+(m-5)/(2m^2-2)
=1/m(m-1)+(m-5)/2(m+1)(m-1)
=2(m+1)/2m(m+1)(m-1)+m(m-5)/2m(m+1)(m-1)
=[2(m+1)+m(m-5)]/2m(m+1)(m-1)
=(m^2-3m+2)/2m(m+1)(m-1)
=(m-1)(m+3)/2m(m+1)(m-1)
=(m+3)/2m(m+1)

前面都一样,最后结果应该是
(m-2)/2m(m+1)