如图平面直角坐标系中,O为原点已知AB两点,A(3,0)B(5/12,m),tan∠AOB=1/2如题,求(1)m=?(2)求过A,B,O三点的二次函数并求顶点C(3)有以OA为直径的圆M,判断BC与圆M的位置关系(1)中m=-6/5已求出直接
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![如图平面直角坐标系中,O为原点已知AB两点,A(3,0)B(5/12,m),tan∠AOB=1/2如题,求(1)m=?(2)求过A,B,O三点的二次函数并求顶点C(3)有以OA为直径的圆M,判断BC与圆M的位置关系(1)中m=-6/5已求出直接](/uploads/image/z/6720073-25-3.jpg?t=%E5%A6%82%E5%9B%BE%E5%B9%B3%E9%9D%A2%E7%9B%B4%E8%A7%92%E5%9D%90%E6%A0%87%E7%B3%BB%E4%B8%AD%2CO%E4%B8%BA%E5%8E%9F%E7%82%B9%E5%B7%B2%E7%9F%A5AB%E4%B8%A4%E7%82%B9%2CA%283%2C0%29B%285%2F12%2Cm%29%2Ctan%E2%88%A0AOB%3D1%2F2%E5%A6%82%E9%A2%98%2C%E6%B1%82%EF%BC%881%EF%BC%89m%3D%3F%EF%BC%882%EF%BC%89%E6%B1%82%E8%BF%87A%2CB%2CO%E4%B8%89%E7%82%B9%E7%9A%84%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0%E5%B9%B6%E6%B1%82%E9%A1%B6%E7%82%B9C%EF%BC%883%EF%BC%89%E6%9C%89%E4%BB%A5OA%E4%B8%BA%E7%9B%B4%E5%BE%84%E7%9A%84%E5%9C%86M%2C%E5%88%A4%E6%96%ADBC%E4%B8%8E%E5%9C%86M%E7%9A%84%E4%BD%8D%E7%BD%AE%E5%85%B3%E7%B3%BB%EF%BC%881%EF%BC%89%E4%B8%ADm%3D-6%2F5%E5%B7%B2%E6%B1%82%E5%87%BA%E7%9B%B4%E6%8E%A5)
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