因式分解 (4x+3y)²-(2x+y)²(a+b+c)²-(a+b-c)²4(2p+3q)²-(3p-q)²(x²+y²)-x²y²
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![因式分解 (4x+3y)²-(2x+y)²(a+b+c)²-(a+b-c)²4(2p+3q)²-(3p-q)²(x²+y²)-x²y²](/uploads/image/z/672504-24-4.jpg?t=%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3+%284x%2B3y%29%26%23178%3B-%282x%2By%29%26%23178%3B%28a%2Bb%2Bc%29%26%23178%3B-%28a%2Bb-c%29%26%23178%3B4%282p%2B3q%29%26%23178%3B-%283p-q%29%26%23178%3B%28x%26%23178%3B%2By%26%23178%3B%29-x%26%23178%3By%26%23178%3B)
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因式分解 (4x+3y)²-(2x+y)²(a+b+c)²-(a+b-c)²4(2p+3q)²-(3p-q)²(x²+y²)-x²y²
因式分解 (4x+3y)²-(2x+y)²
(a+b+c)²-(a+b-c)²
4(2p+3q)²-(3p-q)²
(x²+y²)-x²y²
因式分解 (4x+3y)²-(2x+y)²(a+b+c)²-(a+b-c)²4(2p+3q)²-(3p-q)²(x²+y²)-x²y²
(4x+3y)²-(2x+y)²
= (4x+3y+2x+y)(4x+3y-2x-y)
= (6x+4y)(2x+2y)
=4(3x+2y)(x+y)
(a+b+c)²-(a+b-c)²
=(a+b+c+a+b-c)(a+b+c-a-b+c)
=(2a+2b)(2c)
=4c(a+b)
4(2p+3q)²-(3p-q)²
=[2(2p+3q)+(3p-q)][2(2p+3q)-(3p-q)]
=(7p+5q)(p+7q)
(x²+y²)²-x²y² 有平方吧
=(x²+y²+xy)(x²+y²-xy)