函数f(x)=ln(x+1)-ax∧2-x,a∈R(1)求f(x)的单调区间 (2)求证:对任意的正整数n,不等式ln(n+1/n)<1/n都成立
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![函数f(x)=ln(x+1)-ax∧2-x,a∈R(1)求f(x)的单调区间 (2)求证:对任意的正整数n,不等式ln(n+1/n)<1/n都成立](/uploads/image/z/6747693-69-3.jpg?t=%E5%87%BD%E6%95%B0f%28x%29%3Dln%28x%2B1%29-ax%E2%88%A72-x%2Ca%E2%88%88R%EF%BC%881%EF%BC%89%E6%B1%82f%EF%BC%88x%EF%BC%89%E7%9A%84%E5%8D%95%E8%B0%83%E5%8C%BA%E9%97%B4+%EF%BC%882%EF%BC%89%E6%B1%82%E8%AF%81%EF%BC%9A%E5%AF%B9%E4%BB%BB%E6%84%8F%E7%9A%84%E6%AD%A3%E6%95%B4%E6%95%B0n%2C%E4%B8%8D%E7%AD%89%E5%BC%8Fln%EF%BC%88n%2B1%2Fn%EF%BC%89%EF%BC%9C1%2Fn%E9%83%BD%E6%88%90%E7%AB%8B)
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