若数列﹛an﹜是公差为d的等差数列,则数列a1+a2,a3+a4,a5+a6·········是公差为多少的等差数列?

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若数列﹛an﹜是公差为d的等差数列,则数列a1+a2,a3+a4,a5+a6·········是公差为多少的等差数列?
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若数列﹛an﹜是公差为d的等差数列,则数列a1+a2,a3+a4,a5+a6·········是公差为多少的等差数列?
若数列﹛an﹜是公差为d的等差数列,则数列a1+a2,a3+a4,a5+a6·········是公差为多少的等差数列?

若数列﹛an﹜是公差为d的等差数列,则数列a1+a2,a3+a4,a5+a6·········是公差为多少的等差数列?
若数列﹛an﹜是公差为d的等差数列,则数列a1+a2,a3+a4,a5+a6·········是公差为多少的等差数列?
由数列﹛an﹜是公差为d的等差数列,有通项为
an=a1+(n-1)d,
从而有 a(2n-1)=a1+[(2n-1)-1]d=a1+(2n-2)d
a2n=a1+(2n-1)d
则数列a1+a2,a3+a4,a5+a6·········即数列{aN},有通项为
aN=a(2n-1)+a2n
=[a1+(2n-2)d]+[a1+(2n-1)d]
=2a1+(4n-3)d
=2a1+d+(4n-4)d
=(2a1+d)+(n-1)4d
说明该数列a1+a2,a3+a4,a5+a6·········即数列{aN},是以
(2a1+d)为首项,
公差是4d的等差数列.
∴数列a1+a2,a3+a4,a5+a6·········即数列{aN},的公差是4d.

应该是4d吧

等差数列有性质:S偶次项-S奇次项=50d 由此得出:a2 a4 a6 …… a100=85 则a1 a2 a3 …… a99 a100=145 应该是偶数(下标)之和减去

a1+a2=a1+a1+d=2a1+d
a3+a4=a1+2d+a1+3d=2a1+5d
a5+a6=a1+4d+a1+5d=2a1+9d
d'=4d

2d

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