线性方程,求和(高数)n = 1 时, x1 = a(常数), y1 = x1 * 0.1;n = 2 时, x2 = x1 + y1, y2= x2 *0.1n = 3 时, x3 = x2+y2 , y3= x3 * 0.1n = 4 时, x4 = x3+y3 , y4= x4 * 0.1求:n = p时, xp ,yp 的值.----------
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线性方程,求和(高数)n = 1 时, x1 = a(常数), y1 = x1 * 0.1;n = 2 时, x2 = x1 + y1, y2= x2 *0.1n = 3 时, x3 = x2+y2 , y3= x3 * 0.1n = 4 时, x4 = x3+y3 , y4= x4 * 0.1求:n = p时, xp ,yp 的值.----------
线性方程,求和(高数)
n = 1 时, x1 = a(常数), y1 = x1 * 0.1;
n = 2 时, x2 = x1 + y1, y2= x2 *0.1
n = 3 时, x3 = x2+y2 , y3= x3 * 0.1
n = 4 时, x4 = x3+y3 , y4= x4 * 0.1
求:
n = p时, xp ,yp 的值.
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在线等!答案正确,再追加50分,我都10级了,说话算数.
线性方程,求和(高数)n = 1 时, x1 = a(常数), y1 = x1 * 0.1;n = 2 时, x2 = x1 + y1, y2= x2 *0.1n = 3 时, x3 = x2+y2 , y3= x3 * 0.1n = 4 时, x4 = x3+y3 , y4= x4 * 0.1求:n = p时, xp ,yp 的值.----------
是不是先递推出公式再求值?
n = 1 时,x1 = a(1+0.1)0次方,y1 =【 a(1+0.1)0次方】 * 0.1;
n = 2 时,x2 = a(1+0.1)1次方,y12=【 a(1+0.1)1次方】 * 0.1;
n = 3时,x3 = a(1+0.1)2次方,y3 =【 a(1+0.1)2次方】 * 0.1;
n = 4 时,x4 = a(1+0.1)3次方,y4 =【 a(1+0.1)3次方】 * 0.1;
————
n = p 时,xp =【 a(1+0.1)】(p-1)次方,yp =【 a(1+0.1)】(p-1)次方 * 0.1
仅供参考.
kx+b , (x =1,2,3,4,5,6)
=k(1+2+3+4+5+6)+6b
=6*(6+1)/2*k+6b
=21k+6b
采纳我为最佳把,呵呵。我汗。。。老大,我悬赏这么高的分数,肯定真心求答案的。。 你这个不会做这个题啊,你自己搜索了一下,你这个答案是另外一个百度知道的, 答非所问。。。...
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kx+b , (x =1,2,3,4,5,6)
=k(1+2+3+4+5+6)+6b
=6*(6+1)/2*k+6b
=21k+6b
采纳我为最佳把,呵呵。
收起
n = p时, xp =a*1.1^(p-1), yp =0.1*a*1.1^(p-1)
由题,可知,
y1=x1*0.1,
y2= x2* 0.1=x1(0.1)^2
y3=x3*0.1=x1(0.1)^3
所以:yp=x1(0.1)^p=a(0.1)p,
x1 = a
x2 = x1 + y1
x3 = x2+y2 =x1+y1+y2
x4 = x3+y3 =x1+y1+y2+y3
所以:xp=x1+y1+...
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由题,可知,
y1=x1*0.1,
y2= x2* 0.1=x1(0.1)^2
y3=x3*0.1=x1(0.1)^3
所以:yp=x1(0.1)^p=a(0.1)p,
x1 = a
x2 = x1 + y1
x3 = x2+y2 =x1+y1+y2
x4 = x3+y3 =x1+y1+y2+y3
所以:xp=x1+y1+y2+y3+...+y(p-1)=a+y1+y2+y3+...+y(p-1),
而y1+y2+y3+...+y(p-1)=0.1a[1-0.1^(p-1)]/(1-0.1)=a/9-0.1^(p-1)/9,
所以:xp=10a/9-0.1^(p-1)/9,
综上所述,xp=10a/9-0.1^(p-1)/9,yp=a(0.1)p
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n = P 时, xP = xP-1+y P-1, yP= xP * 0.1
Xp=a*(1.1)^(p-1),Yp=0.1*a*(1.1)^(p-1)