用数学归纳法证明 X^2n-1+y^2n-1能被X+Y整除,从假设n=k成立到n=k+1/成立时,被整除式应为一般从n=k到n=k+1是被整除式是怎么计算的啊A:X^2k+3 + Y^2k+3B:X^2k+2 + Y^2k+2C:X^2k+1 + Y^2k+1D:X^2k + Y^2k
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![用数学归纳法证明 X^2n-1+y^2n-1能被X+Y整除,从假设n=k成立到n=k+1/成立时,被整除式应为一般从n=k到n=k+1是被整除式是怎么计算的啊A:X^2k+3 + Y^2k+3B:X^2k+2 + Y^2k+2C:X^2k+1 + Y^2k+1D:X^2k + Y^2k](/uploads/image/z/6786547-43-7.jpg?t=%E7%94%A8%E6%95%B0%E5%AD%A6%E5%BD%92%E7%BA%B3%E6%B3%95%E8%AF%81%E6%98%8E+X%5E2n-1%2By%5E2n-1%E8%83%BD%E8%A2%ABX%2BY%E6%95%B4%E9%99%A4%2C%E4%BB%8E%E5%81%87%E8%AE%BEn%3Dk%E6%88%90%E7%AB%8B%E5%88%B0n%3Dk%2B1%2F%E6%88%90%E7%AB%8B%E6%97%B6%2C%E8%A2%AB%E6%95%B4%E9%99%A4%E5%BC%8F%E5%BA%94%E4%B8%BA%E4%B8%80%E8%88%AC%E4%BB%8En%3Dk%E5%88%B0n%3Dk%2B1%E6%98%AF%E8%A2%AB%E6%95%B4%E9%99%A4%E5%BC%8F%E6%98%AF%E6%80%8E%E4%B9%88%E8%AE%A1%E7%AE%97%E7%9A%84%E5%95%8AA%3AX%5E2k%2B3+%2B+Y%5E2k%2B3B%3AX%5E2k%2B2+%2B+Y%5E2k%2B2C%3AX%5E2k%2B1+%2B+Y%5E2k%2B1D%3AX%5E2k+%2B+Y%5E2k)
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