若函数f(x)=2sin(wx+∮),x∈r,（其中w＞0,|∮|＜兀/2)的最小正周期是兀,且f(0)=√3

设函数f(x)=sin(wx+t)(-π/2 设函数f(x)=sin(wx+t)(-π/2 已知函数f(x)=sin (wx+兀/3)-cOs (wx+兀/6)-2sin ^2 wx/2+1已知函数f(x)=sin (wx+兀/3)-cOs (wx+兀/6)-2sin ^2 wx/2+1,w>0,x∈R.①若函数f(x)的周期为兀,求w.②在①的条件下,求函数f(x)在区间[-兀/4,兀/4]上的最大值和最 已知函数f(x)=sin(wx+φ)(w 函数f(x)=sin(wx+φ)(w>0,|φ| 已知函数f(x)=sin(wx+φ)(w 函数f(x)=sin(wx+φ)(w>0,|φ| 函数f(X)=sin(wx+φ)(w>0,|φ| 已知函数f(x)=sin(wx+φ)(w 已知函数f(X)=sin(Wx+&)(W>0,0 已知函数f(x)=2sin(wx+φ),x属于R,w>0,-π 已知函数f x=√3sin(wx+φ/2)*cos(wx+φ/2)+sin^2(wx+φ/2)(w>0,0 若函数f（x）=2sin（wx+b）,x属于R（b>0,|b| 已知函数f（x）=sin wx-cos wx最小周期为π 求w 若f（a/2）=1/3求sin2a的值 若函数f(x)=sin(wx+阿发)+cos(wx+阿发)(w>0,绝对值阿发 设函数f(x)=sin(wx+φ)+cos(wx+φ)(w>0,|φ| 设函数f(x)=sin(wx+φ)+cos(wx+φ)(w>0,|φ| 设函数f(x)=sin(wx+φ)+cos(wx+φ)(w>0,|φ|