(1/2)设函数f(x)(x属于R)是以2为周期的函数,且x属于[0,2]时f(x)=(x-1)的平方.当x属于[2,4]时,求f(...(1/2)设函数f(x)(x属于R)是以2为周期的函数,且x属于[0,2]时f(x)=(x-1)的平方.当x属于[2,4]时,求f(x)的解析式
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![(1/2)设函数f(x)(x属于R)是以2为周期的函数,且x属于[0,2]时f(x)=(x-1)的平方.当x属于[2,4]时,求f(...(1/2)设函数f(x)(x属于R)是以2为周期的函数,且x属于[0,2]时f(x)=(x-1)的平方.当x属于[2,4]时,求f(x)的解析式](/uploads/image/z/6792266-2-6.jpg?t=%281%2F2%29%E8%AE%BE%E5%87%BD%E6%95%B0f%28x%29%28x%E5%B1%9E%E4%BA%8ER%29%E6%98%AF%E4%BB%A52%E4%B8%BA%E5%91%A8%E6%9C%9F%E7%9A%84%E5%87%BD%E6%95%B0%2C%E4%B8%94x%E5%B1%9E%E4%BA%8E%5B0%2C2%5D%E6%97%B6f%28x%29%3D%28x-1%29%E7%9A%84%E5%B9%B3%E6%96%B9.%E5%BD%93x%E5%B1%9E%E4%BA%8E%5B2%2C4%5D%E6%97%B6%2C%E6%B1%82f%28...%281%2F2%29%E8%AE%BE%E5%87%BD%E6%95%B0f%28x%29%28x%E5%B1%9E%E4%BA%8ER%29%E6%98%AF%E4%BB%A52%E4%B8%BA%E5%91%A8%E6%9C%9F%E7%9A%84%E5%87%BD%E6%95%B0%2C%E4%B8%94x%E5%B1%9E%E4%BA%8E%5B0%2C2%5D%E6%97%B6f%28x%29%3D%28x-1%29%E7%9A%84%E5%B9%B3%E6%96%B9.%E5%BD%93x%E5%B1%9E%E4%BA%8E%5B2%2C4%5D%E6%97%B6%2C%E6%B1%82f%28x%29%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F)
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(1/2)设函数f(x)(x属于R)是以2为周期的函数,且x属于[0,2]时f(x)=(x-1)的平方.当x属于[2,4]时,求f(...(1/2)设函数f(x)(x属于R)是以2为周期的函数,且x属于[0,2]时f(x)=(x-1)的平方.当x属于[2,4]时,求f(x)的解析式
(1/2)设函数f(x)(x属于R)是以2为周期的函数,且x属于[0,2]时f(x)=(x-1)的平方.当x属于[2,4]时,求f(...
(1/2)设函数f(x)(x属于R)是以2为周期的函数,且x属于[0,2]时f(x)=(x-1)的平方.当x属于[2,4]时,求f(x)的解析式
(1/2)设函数f(x)(x属于R)是以2为周期的函数,且x属于[0,2]时f(x)=(x-1)的平方.当x属于[2,4]时,求f(...(1/2)设函数f(x)(x属于R)是以2为周期的函数,且x属于[0,2]时f(x)=(x-1)的平方.当x属于[2,4]时,求f(x)的解析式
令x属于[2,4],
则
x-2属于[0,2]
此时有f(x)=(x-1)的平方
所以
f(x-2)=(x-2-1)的平方=(x-3)的平方
又f(x)(x属于R)是以2为周期的函数,
所以
f(x)=f(x-2)
即
f(x)=(x-3)的平方.
函数f(x) (x属于R) 是以2为最小正周期
所以 f(x)=f(x-2k)
令 0