15x^2-11x+2/-2x^2+3x+2
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15x^2-11x+2/-2x^2+3x+2
15x^2-11x+2/-2x^2+3x+2
15x^2-11x+2/-2x^2+3x+2
因为X^2=3X+1 所以2X^3=2X*(3X+1) 所以2x^3-3x^2-11x+8=2X*(采用降次法∵x^2-3x-1=0 ∴x^2=3x+1 2x^2-3x=1 2x^3-3x^2-
15
x(x*x-6x-9)-x(x*x-8x-15)+2x(3-x)
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{x|(x+3)(x-2)
-x^3+x^2-x
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X(x平方-6x-9)-x(x平方-8x-15)+2x(3-x)其中x=-六分之一
计算:[(x+2)/(x+3) - (x+1)/(x+2) + (x+4)/(x+5) - (x+3)/(x+4) / (x^2 + 7x + 13)/(x^2 + 8x + 15)
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