设abc=1,求a÷(ab+b+1)+b÷(bc+b+1)+c÷(ac+c+1)
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设abc=1,求a÷(ab+b+1)+b÷(bc+b+1)+c÷(ac+c+1)
设abc=1,求a÷(ab+b+1)+b÷(bc+b+1)+c÷(ac+c+1)
设abc=1,求a÷(ab+b+1)+b÷(bc+b+1)+c÷(ac+c+1)
(1)因为abc=1.
a/(ab+a+1)+b/(bc+b+1)+c/(ac+c+1)
=a/(ab+a+1)+ab/(abc+ab+a)+abc/(abac+abc+ab)
=a/(ab+a+1)+ab/(1+ab+a)+1/(a+1+ab)
=(ab+a+1)/(ab+a+1)
=1