a=(2,-3,1),b=(1,-2,3),c=(2,1,2),向量r满足r⊥b,r⊥a,prjc R(即r在c上的投影了,符号太难打了)=14求r
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a=(2,-3,1),b=(1,-2,3),c=(2,1,2),向量r满足r⊥b,r⊥a,prjc R(即r在c上的投影了,符号太难打了)=14求r
a=(2,-3,1),b=(1,-2,3),c=(2,1,2),向量r满足r⊥b,r⊥a,prjc R(即r在c上的投影了,符号太难打了)=14求r
a=(2,-3,1),b=(1,-2,3),c=(2,1,2),向量r满足r⊥b,r⊥a,prjc R(即r在c上的投影了,符号太难打了)=14求r
设与a,b垂直的向量为k=(x,y,z)
则 2x-3y+z=0
x-2y+3z=0
令 x=7,y=5,z=1,满足
则 r=t (7,5,1)
|c|=3
∴ r在c上的投影为 t*(14+5+2)/|c|=14
∴ t*21=42
∴ t=2
∴ r=(14,10,2)