化简:cos(90°+α)·csc(370°+α)·tan(180°-α)/sec(360°-α)·sin(180°+α)·cot(90°-α)·是乘号.最后答案是1.求过程.= =。啊sorry……是270°……我看错了。呃。【cos(90°+α)·csc(270°+α)·tan(180°-α)】/【sec(360°-

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化简:cos(90°+α)·csc(370°+α)·tan(180°-α)/sec(360°-α)·sin(180°+α)·cot(90°-α)·是乘号.最后答案是1.求过程.= =。啊sorry……是270°……我看错了。呃。【cos(90°+α)·csc(270°+α)·tan(180°-α)】/【sec(360°-
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化简:cos(90°+α)·csc(370°+α)·tan(180°-α)/sec(360°-α)·sin(180°+α)·cot(90°-α)·是乘号.最后答案是1.求过程.= =。啊sorry……是270°……我看错了。呃。【cos(90°+α)·csc(270°+α)·tan(180°-α)】/【sec(360°-
化简:cos(90°+α)·csc(370°+α)·tan(180°-α)/sec(360°-α)·sin(180°+α)·cot(90°-α)
·是乘号.最后答案是1.求过程.
= =。啊sorry……是270°……我看错了。呃。
【cos(90°+α)·csc(270°+α)·tan(180°-α)】/【sec(360°-α)·sin(180°+α)·cot(90°-α)】

化简:cos(90°+α)·csc(370°+α)·tan(180°-α)/sec(360°-α)·sin(180°+α)·cot(90°-α)·是乘号.最后答案是1.求过程.= =。啊sorry……是270°……我看错了。呃。【cos(90°+α)·csc(270°+α)·tan(180°-α)】/【sec(360°-
还是原来的题目错了,现在对了

cos(90°+α)·csc(270°+α)·tan(180°-α)/sec(360°-α)·sin(180°+α)·cot(90°-α)
=sin(-a)*(-1/cosa) * tan(-a) / (1/cos(a))sin(-a)tan(a)
=1
终于和答案对上了
采纳我吧