log(1/8)X
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log(1/8)X
log(1/8)X
log(1/8)X
f(x) = (1/8)^x是单调递减函数
所以由log(1/8)X < 1/3
可得(1/8)^[log(1/8)X] > (1/8)^(1/3)
得X > (1/8)^(1/3)
即X > 1/2
log(1/8)X
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