cos(x+π/6)=-1/2,怎么求x、?

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cos(x+π/6)=-1/2,怎么求x、?
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cos(x+π/6)=-1/2,怎么求x、?
cos(x+π/6)=-1/2,怎么求x、?

cos(x+π/6)=-1/2,怎么求x、?
cos(x+π/6)=-1/2
x+π/6=2π/3+2kπ或x+π/6=4π/3+2kπ
x=π/2+2kπ或x=7π/6+2kπ (k∈Z)

cos(2π/3)=-1/2
x=π/2
或者2kπ+2/3π 或 2kπ+4/3π(k是整数)
。。。你带入减一下