x^2/(x-1)^10 dx求不定积分详细过程 急

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/26 08:28:35
x^2/(x-1)^10 dx求不定积分详细过程 急
xRMK0+AZB&,ŶgYZ׫ŋ_ l۽_p6Uеf޼&daŌE͘PUOqRM|ֳ?Cэw@j!>">We1RFb&L"6~HdX0C-r1BZ_DRڒ#+d$t*ݮP04#~s'GA<5~*J!Cc!~e.-j;;$K~@9T)v۰A ]mJW/MD+m"R3%WwPlr4LjveP %mlX8JNɴMܨ{(U

x^2/(x-1)^10 dx求不定积分详细过程 急
x^2/(x-1)^10 dx求不定积分详细过程 急

x^2/(x-1)^10 dx求不定积分详细过程 急
x^2/(x-1)^10
说明:x^2=(x-1+1)^2=(x-1)^2+2(x-1)+1
x^2/(x-1)^10
=((x-1)^2+2(x-1)+1)/(x-1)^10
=1/(x-1)^8+(2(x-1)+1)/(x-1)^10
=(x-1)^(-8) +2 (x-1)^(-9) +(x-1)^(-10)
原式=∫[(x-1)^(-8) +2 (x-1)^(-9) +(x-1)^(-10)]d(x-1)
=-[1/[7(x-1)^7]-[2/[8(x-1)^(-8)]-[1/[9(x-1)^(-9)] + C
=-1/[7(x-1)^7]-1/[4(x-1)^8]-1/[9(x-1)^9]+C

令x-1=t
∫x^2/(x-1)^10 dx

=∫(t+1)²/t^10dt
=∫(1/t^8+2/t^9+1/t^10)dt
=-1/7t^7-1/4t^8-1/9t^9+C
=-1/[7(x-1)^7]-1/[4(x-1)^8]-1/[9(x-1)^9]+C


∫x^2/(x-1)^10 dx
=∫[1/(x-1)^8+2/(x-1)^9+1/(x-1)^10]dx
=∫1/(x-1)^8 dx+2∫1/(x-1)^9 dx+∫1/(x-1)^10 dx
=∫1/(x-1)^8 d(x-1)+2∫1/(x-1)^9 d(x-1)+∫1/(x-1)^10 d(x-1)
=(-1/7)·1/(x-1)^7+(-2/8)·1/(x-1)^8+(-1/9)·1/(x-1)^9+C
=-1/[7(x-1)^7]-1/[4(x-1)^8]-1/[9(x-1)^9]+C