Find the number of three-digit numbers possible if only the digits 0,1,2,3,4and5 may be used,the number must be a multiple of 5,and no digit may be used more than twice in the same number

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Find the number of three-digit numbers possible if only the digits 0,1,2,3,4and5 may be used,the number must be a multiple of 5,and no digit may be used more than twice in the same number
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Find the number of three-digit numbers possible if only the digits 0,1,2,3,4and5 may be used,the number must be a multiple of 5,and no digit may be used more than twice in the same number
Find the number of three-digit numbers possible if only the digits 0,1,2,3,4and5 may be used,the number must be a multiple of 5,and no digit may be used more than twice in the same number

Find the number of three-digit numbers possible if only the digits 0,1,2,3,4and5 may be used,the number must be a multiple of 5,and no digit may be used more than twice in the same number
一个三位数,只能由0,1,2,3,4,5来组成,它必须是5的倍数,这个数中每个数字使用不能超过2次.这样的数有几个?
必须是5的倍数,说明最后一位只能是0或5.
第一位数可以是1-5中任意一个,第二位数可以是0-5中任意一个,第三位数是0或者5.
概率是5 x 6 x 2 = 60
因为每个数不能用两次以上,上面唯一一个例外是555这个数,去掉以后是59个.
所以可以有59个这样的数.

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找到三位数字的数目可用于可能的，如果只有数字0,1,2,3,4和5，这个数必须是5的倍数，也可以使用没有数字的两倍以上的相同数目找到三位数字的数目可用于可能的，如果只有数字0,1,2,3,4和5，这个数必须是5的倍数，也可以使用没有数字的两倍以上的相同数目找到三位数字的数目可用于可能的，如果只有数字0,1,2,3,4和5，这个数必须是5的倍数，也可以使用没有数字的两倍以上的相同数目...

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找到三位数字的数目可用于可能的，如果只有数字0,1,2,3,4和5，这个数必须是5的倍数，也可以使用没有数字的两倍以上的相同数目

收起

这题目我还真不懂，不能超过5。哎，

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