若对一切x属于R,x^4+ax^2+1=>(大于等于)0恒成立,求a的范围?
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若对一切x属于R,x^4+ax^2+1=>(大于等于)0恒成立,求a的范围?
若对一切x属于R,x^4+ax^2+1=>(大于等于)0恒成立,求a的范围?
若对一切x属于R,x^4+ax^2+1=>(大于等于)0恒成立,求a的范围?
原式可变为(x^2)^2+ax^2+1≥0
根据二次函数图像或二次不等式解法得:
△=a^2-4≤0=>-2≤a≤2
令x^2=t则原式化为t^2+at+1>=0(t>=0)△=a^2-4≤0
-2<=a<=2