5x²-mx+n 因式分解 ﹙5x-60﹚﹙x+20﹚ 求m,n
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/10 21:55:57
![5x²-mx+n 因式分解 ﹙5x-60﹚﹙x+20﹚ 求m,n](/uploads/image/z/6853912-16-2.jpg?t=5x%26%23178%3B-mx%2Bn+%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3+%EF%B9%995x-60%EF%B9%9A%EF%B9%99x%2B20%EF%B9%9A+%E6%B1%82m%2Cn)
x)3PS64ͭSx:{=O;^,_~L
]3;gF ³M:y6IEd/f
20c
@J*t
L
]͵51Q \[]<[&<;7lTbu2~>eӾF/E w<.z DNyY`tLQ X=o5O
@Rtv ˢx٢w>5g/|>{Mxw
9
5x²-mx+n 因式分解 ﹙5x-60﹚﹙x+20﹚ 求m,n
5x²-mx+n 因式分解 ﹙5x-60﹚﹙x+20﹚ 求m,n
5x²-mx+n 因式分解 ﹙5x-60﹚﹙x+20﹚ 求m,n
﹙5x-60﹚﹙x+20﹚
=5x²+100x-60x-1200
=5x²+40x-1200
=5x²-mx+n
-m=40, m=-40
n=-1200
5x²-mx+n =﹙5x-60﹚﹙x+20﹚=5x²+40x-1200
m=-40
n=-1200
﹙5x-60﹚﹙x+20﹚
=5x²+100x-60x-1200
=5x²+40x-1200
由原式5x²-mx+n 可知
m=-40 n=-1200
答案:m=-40,n=-1200
﹙5x-60﹚﹙x+20﹚去括号:
=5x^2+100x-60x-1200
=5x^2+40x-1200
对应5x²-mx+n 项相等
得:m=-40,n=-1200