x+2y+3z=15(x+4y)/3=(y-3z)/4=3这个方程组怎么解

x+y/2=z+x/3=y+z/4 x+y+z=27 x+2y=3x+2z=4y+z 求x:y:z 已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) x+2y+3z=10,4x+3y+2z=15则x+y+z= x+2y+3Z=10,4x+3y+2z=15,求x+y+z= 2x+y+3z=10,3x+4y+2z=15,则x+y+z= (4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=? 2x+3y-z=9,x+y+z=15,5x-4y-z=0 2x+3y+z=13 4x^2+9y^2+z^2-2x+15y+3z=82 求x,y,z (4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian 设|x|-|y|+|z|=|x+y+z|,且|x+y|=4,|y+z|=5,|y|=3,求(x-y-z)^2的值 2x+z=10 x+y-z=4 3x-y-z=0 x+y=5 2x+3y-z=9 x-y+z=4 {2x+y=10 {x-y+z=4 {3x-y-z=0 x=y/z=z/3,x+y+z ＝12,求2x+3y+4z是多少, (4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊 证明 ：x/(y+z)+y/(z+x)+z/(x+y)>=3/2其中 x,y,z>0