直线y=x+1交x轴于点P,交椭圆x^2/a^2+y^2/b^2=1(a>b>0)于相异两点A、B,且向量PA=-3向量PB(1)求a的取值范围(2)将弦AB绕点A逆时针旋转90°得到线段AQ,设点Q坐标为(m,n)求证m+7n=-1题上那个是向量PA=-3
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![直线y=x+1交x轴于点P,交椭圆x^2/a^2+y^2/b^2=1(a>b>0)于相异两点A、B,且向量PA=-3向量PB(1)求a的取值范围(2)将弦AB绕点A逆时针旋转90°得到线段AQ,设点Q坐标为(m,n)求证m+7n=-1题上那个是向量PA=-3](/uploads/image/z/6854995-19-5.jpg?t=%E7%9B%B4%E7%BA%BFy%3Dx%2B1%E4%BA%A4x%E8%BD%B4%E4%BA%8E%E7%82%B9P%2C%E4%BA%A4%E6%A4%AD%E5%9C%86x%5E2%2Fa%5E2%2By%5E2%2Fb%5E2%3D1%28a%3Eb%3E0%29%E4%BA%8E%E7%9B%B8%E5%BC%82%E4%B8%A4%E7%82%B9A%E3%80%81B%2C%E4%B8%94%E5%90%91%E9%87%8FPA%3D-3%E5%90%91%E9%87%8FPB%EF%BC%881%EF%BC%89%E6%B1%82a%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%EF%BC%882%EF%BC%89%E5%B0%86%E5%BC%A6AB%E7%BB%95%E7%82%B9A%E9%80%86%E6%97%B6%E9%92%88%E6%97%8B%E8%BD%AC90%C2%B0%E5%BE%97%E5%88%B0%E7%BA%BF%E6%AE%B5AQ%2C%E8%AE%BE%E7%82%B9Q%E5%9D%90%E6%A0%87%E4%B8%BA%EF%BC%88m%2Cn%EF%BC%89%E6%B1%82%E8%AF%81m%2B7n%3D-1%E9%A2%98%E4%B8%8A%E9%82%A3%E4%B8%AA%E6%98%AF%E5%90%91%E9%87%8FPA%3D-3)
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