(2x+1)(xy-2)=2xy X-2y=4 求x,y速度呀
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/05 22:46:46
x)06Ԩ5Ҵ5T55QxBe=`TO@-X ;HDU<Ɏ]u6<ٽ"eogkRkia ~ھ+BO[BE$] `6
(2x+1)(xy-2)=2xy X-2y=4 求x,y速度呀
(2x+1)(xy-2)=2xy X-2y=4 求x,y
速度呀
(2x+1)(xy-2)=2xy X-2y=4 求x,y速度呀
X-2y=4,X-4=2y,因为(2x+1)(xy-2)=2xy所以(2x+1)*1/2*(X^2-4x-4)=X^2-4x,求出X,代入X-2y=4求Y.
3xy(x^2-xy^2+xy)-xy^2(2x^2-xy+2x)
化简:xy分之3x^2+2xy-xy分之2x^2-xy=
已知x+y=1,xy=-2,则x²y+xy²-2xy
1-2/x+y=xy,4y+6x=xy.求xy的解?
已知(x+1)*(x+1)=-Iy-1I,求2(xy-(5xy)*(5xy))-3((xy)*(xy)-xy)
( )-(x^2+3xy)=-xy-1/3y^2
因式分解2x^-xy
.(x+y-2)(x+y-2xy)+(xy-1)^2
因式分解x^3+2xy-x-xy^2=
计算3xy[2xy-x(y-2)+x-1]
1-(3xy-x)+【-2(2x+3xy)】
(-3x^y+2xy)-( )=4x^+xy
x³+2xy-x-xy²=(因式分解)
(XY-X^2)除以X-Y/XY=?
已知1/x-1/y=2,求3x+7xy-3y/2x-3xy-2y答案是1/x-1/y=2(y-x)/xy=2 得:x-y=-2xy(3x+7xy-3y)/(2x-3xy-2y)=[3(x-y)+7xy]/[2(x-y)-3xy]=(-6xy+7xy)/(-4xy-3xy)=xy/(-7xy)=-1/7 谁能帮我解释一下=[3(x-y)+7xy]/[2(x-y)-3xy]=(-6xy+7xy)/(-4xy-3xy) 是怎
因式分解X^3-2xy+xy^2
x^2-xy/xy-y^2约分
因式分解:-xy^2+2xy-x