已知x,y满足2x^2-2xy+y^2+2x+1=0,求(xy)^2010的值.
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已知x,y满足2x^2-2xy+y^2+2x+1=0,求(xy)^2010的值.
已知x,y满足2x^2-2xy+y^2+2x+1=0,求(xy)^2010的值.
已知x,y满足2x^2-2xy+y^2+2x+1=0,求(xy)^2010的值.
原式可化成 (x-y)²+(x+1)²=0
所以 x=y=-1,xy=1,(xy)^2010=1
(x-y)^2+(x+1)^2=0
suoyi x=-1,y=x=-1,suoyi (xu)^2010=(-1)^2010=1