若√x+y-1+(y+4)²=0,则x-y的值是多少?
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若√x+y-1+(y+4)²=0,则x-y的值是多少?
若√x+y-1+(y+4)²=0,则x-y的值是多少?
若√x+y-1+(y+4)²=0,则x-y的值是多少?
要使原式等于0,必须同时满足x+y-1=0和y+4=0
解得x=5,y=-4
x-y=9