因式分解x(x-1)(x+2)(x+3)-40 要具体过程.

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因式分解x(x-1)(x+2)(x+3)-40 要具体过程.
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因式分解x(x-1)(x+2)(x+3)-40 要具体过程.
因式分解x(x-1)(x+2)(x+3)-40 要具体过程.

因式分解x(x-1)(x+2)(x+3)-40 要具体过程.

原式=(x^2+2x)(x^2+2x-3)-40
=(x^2+2x)^2-3(x^2+2x)-40
=(x^2+2x-8)(x^2+2x+5)
=(x+4)(x-2)(x^2+2x+5)

因式分解x(x-1)(x+2)(x+3)-40
[x(x+2)][(x-1)(x+3)]-40=(x²+2x)(x²+2x-3)-40=(x²+2x)²-3(x²+2x)-40
=(x²+2x-8)(x²+2x+5)=(x+4)(x-2)(x²+2x+5)

答:
x(x-1)(x+2)(x+3)-40
=[x(x+2)]*[(x-1)(x+3)]-40
=(x^2+2x)*(x^2+2x-3)-40
=(x^2+2x)^2-3(x^2+2x)-8*5
=(x^2+2x-8)(x^2+2x+5)
=(x-2)(x+4)(x^2+2x+5)