作业帮(z-x)^2-4(x-y)(y-z)=0求证x+z-2y=0_
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(z-x)^2-4(x-y)(y-z)=0求证x+z-2y=0_
(z-x)^2-4(x-y)(y-z)=0求证x+z-2y=0_
(z-x)^2-4(x-y)(y-z)=0求证x+z-2y=0_
(z-x)^2-4(x-y)(y-z)=0
(z-x)^2=(x-z)^2=[(x-y)+(y-z)]^2
[(x-y)+(y+z)]^2-4(x-y)(y-z)=0
(x-y)^2+(y-z)^2-2(x-y)(y-z)=0
[(x-y)-(y-z)]^2=0
(x+z-2y)^2=0
x+z-2y=0
(z-x)^2-4(x-y)(y-z)=0
(x-z)^2-4(x-y)(y-z)=0
[(x-y)+(y-z)]^2-4(x-y)(y-z)=0
(x-y)^2+2(x-y)(y-z)+(y-z)^2-4(x-y)(y-z)=0
(x-y)^2-2(x-y)(y-z)+(y-z)^2=0
[(x-y)-(y-z)]^2=0
所以(x-y)-(y-z)=0
x+z-2y=0
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若x,y,z成等差数列,则(z-x)^2-4(x-y)(y-x)=