等式根号下(2x-1)/(x-3)=根号下2x-1除以根号下x-3成立的条件是?
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等式根号下(2x-1)/(x-3)=根号下2x-1除以根号下x-3成立的条件是?
等式根号下(2x-1)/(x-3)=根号下2x-1除以根号下x-3成立的条件是?
等式根号下(2x-1)/(x-3)=根号下2x-1除以根号下x-3成立的条件是?
根号下(2x-1)/(x-3)=根号下2x-1除以根号下x-3成立的条件是:
2x-1>=0
x-3>0
x>=1/2且x>3
所以,所求条件为x>3
根号下(2x-1)/(x-3)=根号下2x-1除以根号下x-3成立的条件是:
2x-1>=0
x-3>0