(a+2b-1)²与(2x+y+z)(2x-y-z)这两题请详解,
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/12 16:51:53
![(a+2b-1)²与(2x+y+z)(2x-y-z)这两题请详解,](/uploads/image/z/6859511-71-1.jpg?t=%28a%2B2b-1%29%26%23178%3B%E4%B8%8E%282x%2By%2Bz%29%282x-y-z%29%E8%BF%99%E4%B8%A4%E9%A2%98%E8%AF%B7%E8%AF%A6%E8%A7%A3%2C)
x)H6J5TS64~OèBRJHVVi?Ɏ%/x~^,_cTOF;
|w_,k(xcӍSix5Ov4 PMN cZ("F5IL5J6IuM
i
YITQXDJCUWVVA6yvвsP}
[&L?mCF`U(@bGؼҨf!o rKTp8 i
(a+2b-1)²与(2x+y+z)(2x-y-z)这两题请详解,
(a+2b-1)²与(2x+y+z)(2x-y-z)这两题请详解,
(a+2b-1)²与(2x+y+z)(2x-y-z)这两题请详解,
你是要这两个展开么?第一个(a+2b-1)²=[a+(2b-1)]²=a²+2a(2b-1)+(2b-1)²=a²+4ab-2a+4b²-4b+1 (2x+y+z)(2x-y-z)=[2x+(y+z)][2x-(y+z)]=4x²-2x(y+z)+2x(y+z)-(y+z)²=4x²-y²-2yz-z²
(a+2b-1)²
=(a+2b)²-2(a+2b)+1
=a²+4ab+4b²-2a-4b+1
(2x+y+z)(2x-y-z)
=[2x+(y+z)][2x-(y+z)]
=(2x)²-(y+z)²
=4x²-y²-2yz-z²
(a+2b-1)²
=(a+2b)²-2(a+2b)+1
=a²+4ab+4b²-2a-4b+1
(2x+y+z)(2x-y-z)
=(2x)²-(y+z)²
=4x²-y²-2yz-z²