【(axa-1/a-1)+1】/(a+1)x(axa-1/axa+2a)

来源:学生作业帮助网 编辑:作业帮 时间:2024/10/02 17:58:20
【(axa-1/a-1)+1】/(a+1)x(axa-1/axa+2a)
x){0ĊD]C} ~SqD}6[H6J $铧QΆ;6ZLS(& cb#I%F`P-ՁՀEl ~sOYR̼D]# _|AXH' 6@*c1HD,-C}#mHV2[D|9

【(axa-1/a-1)+1】/(a+1)x(axa-1/axa+2a)
【(axa-1/a-1)+1】/(a+1)x(axa-1/axa+2a)

【(axa-1/a-1)+1】/(a+1)x(axa-1/axa+2a)
原式=[(a+1)(a-1)/(a-1)+1]/(a+1)×(a+1)(a-1)/a(a+2)
=[(a+1)+1]/(a+1)×(a+1)(a-1)/a(a+2)
=(a+2)/(a+1)×(a+1)(a-1)/a(a+2)
=(a-1)/a

用a
原式=2sina-2(sinacosπ/3-cosasinπ/3)
=2sina-sina+√3cosa
=sina+√3cosa
=2(sina*1/2+cosa*√3/2)
=2(sinacosπ/3+cosasinπ/3)
=2sin(a+π/3)