在△ABC中,向量m=(cos A/2,-sinA/2),向量n=(cosA/2,sinA/2),且m×n=根号2/2在△ABC中,向量m=(cos A/2,-sinA/2),向量n=(cosA/2,sinA/2),且m×n=√2/2 ①,求∠A.②,若边a=√5 ,S△=3 ,求边 b 和 c .
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/31 03:49:51
![在△ABC中,向量m=(cos A/2,-sinA/2),向量n=(cosA/2,sinA/2),且m×n=根号2/2在△ABC中,向量m=(cos A/2,-sinA/2),向量n=(cosA/2,sinA/2),且m×n=√2/2 ①,求∠A.②,若边a=√5 ,S△=3 ,求边 b 和 c .](/uploads/image/z/6870816-0-6.jpg?t=%E5%9C%A8%E2%96%B3ABC%E4%B8%AD%2C%E5%90%91%E9%87%8Fm%3D%EF%BC%88cos+A%2F2%2C-sinA%2F2%29%2C%E5%90%91%E9%87%8Fn%3D%EF%BC%88cosA%2F2%2CsinA%2F2%29%2C%E4%B8%94m%C3%97n%3D%E6%A0%B9%E5%8F%B72%2F2%E5%9C%A8%E2%96%B3ABC%E4%B8%AD%2C%E5%90%91%E9%87%8Fm%3D%EF%BC%88cos+A%2F2%2C-sinA%2F2%29%2C%E5%90%91%E9%87%8Fn%3D%EF%BC%88cosA%2F2%2CsinA%2F2%29%2C%E4%B8%94m%C3%97n%3D%E2%88%9A2%2F2+%E2%91%A0%2C%E6%B1%82%E2%88%A0A.%E2%91%A1%2C%E8%8B%A5%E8%BE%B9a%3D%E2%88%9A5+%2CS%E2%96%B3%3D3+%2C%E6%B1%82%E8%BE%B9+b+%E5%92%8C+c+.)
xYms+ǟbSY7b1cՕxwٻ*&(4$)MB_v>/9wweIR}qi)Ƈ|Uvrj;>|kye)MّtbX.97xfG6IBn@ =xޝ_?(|lj~zOP"2c+0Jyjw,J#*FNfhoGOu05Ncom+*C͑x}Ѕ`lƽ"mҬKps֗Zvn2tb2cd.CH^<#@v_7".3YPX5#*D+?3Bw7jnB/'%,|oa32c |įSf0hSlW3vx# On_:?)4i|KBLgB`τLm$wap^vcs8,o3Ўhr#ud2ƛ~qwS}4j"a&Ѣx8@
8M;x={57o6|P֕nػ߿6sFX붤
ZeEÔH߶1MU@+n@)izYU/(g%VKMPz45J>BKB'?YI.HtTVViI4
P$>aدTv@L&hzjSEVyWlKc]Ւ.A+_'iUٖR"`ۭi݁&FRS`>D`!Dd\@hmx256!&T7n+پC:'
eA5/azRuH
o )I,
|(jDMjU*JWT$ٺ!~ZC~v|!cӝ~՝`
k-,{2(=$ĉ2