已知,在△ABC中,∠BAC的平分线AD和BC边上的中垂线GD交于D,DE⊥AB于E,DF⊥AC交AC的延长线F,求证:(1)BE=CF:(2)AB+AC=2AE
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![已知,在△ABC中,∠BAC的平分线AD和BC边上的中垂线GD交于D,DE⊥AB于E,DF⊥AC交AC的延长线F,求证:(1)BE=CF:(2)AB+AC=2AE](/uploads/image/z/6871049-17-9.jpg?t=%E5%B7%B2%E7%9F%A5%2C%E5%9C%A8%E2%96%B3ABC%E4%B8%AD%2C%E2%88%A0BAC%E7%9A%84%E5%B9%B3%E5%88%86%E7%BA%BFAD%E5%92%8CBC%E8%BE%B9%E4%B8%8A%E7%9A%84%E4%B8%AD%E5%9E%82%E7%BA%BFGD%E4%BA%A4%E4%BA%8ED%2CDE%E2%8A%A5AB%E4%BA%8EE%2CDF%E2%8A%A5AC%E4%BA%A4AC%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BFF%2C%E6%B1%82%E8%AF%81%3A%281%29BE%3DCF%EF%BC%9A%EF%BC%882%EF%BC%89AB%2BAC%3D2AE)
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