已知圆O1与圆O2相交于点BC,AB是圆O1的直径,ABAC的延长线分别交于圆O2于点DE,过点B作圆O1的切线交AB于点F
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![已知圆O1与圆O2相交于点BC,AB是圆O1的直径,ABAC的延长线分别交于圆O2于点DE,过点B作圆O1的切线交AB于点F](/uploads/image/z/6873021-45-1.jpg?t=%E5%B7%B2%E7%9F%A5%E5%9C%86O1%E4%B8%8E%E5%9C%86O2%E7%9B%B8%E4%BA%A4%E4%BA%8E%E7%82%B9BC%2CAB%E6%98%AF%E5%9C%86O1%E7%9A%84%E7%9B%B4%E5%BE%84%2CABAC%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E5%88%86%E5%88%AB%E4%BA%A4%E4%BA%8E%E5%9C%86O2%E4%BA%8E%E7%82%B9DE%2C%E8%BF%87%E7%82%B9B%E4%BD%9C%E5%9C%86O1%E7%9A%84%E5%88%87%E7%BA%BF%E4%BA%A4AB%E4%BA%8E%E7%82%B9F)
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已知圆O1与圆O2相交于点BC,AB是圆O1的直径,ABAC的延长线分别交于圆O2于点DE,过点B作圆O1的切线交AB于点F
已知圆O1与圆O2相交于点BC,AB是圆O1的直径,ABAC的延长线分别交于圆O2于点DE,过点B作圆O1的切线交AB于点F
已知圆O1与圆O2相交于点BC,AB是圆O1的直径,ABAC的延长线分别交于圆O2于点DE,过点B作圆O1的切线交AB于点F
如图,已知圆O1与圆O2相交于B,C.AB是圆O1的直径,AB,AC到底延长线分别交圆O2于点D,E过B点作O1到底切线交AE于F,求证BF平行DE.
连BC,BE
∵AB是直径
∴BC⊥AC(直径所对的圆周角是直角)
∴BE是直径(直角所对的弦是直径)
∴AD⊥DE(直径所对的圆周角是直角)
∵BF是切线
∴AD⊥BF
∴BF∥DE(同一平面内垂直于同一直线的两直线平行)
请指教呀!