f(x)=ln((√(1+x2))-x)的单调性,
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f(x)=ln((√(1+x2))-x)的单调性,
f(x)=ln((√(1+x2))-x)的单调性,
f(x)=ln((√(1+x2))-x)的单调性,
答:
f(x)=ln[√(1+x²)-x]
设g(x)=√(1+x²)-x
求导得:g'(x)=x/√(1+x²)-1