化简√1+1/n²+(n+1)²得 [1+1/n²+(n+1)²]在根号内.计算:√(1+1/1²+1/2²)+√(1+1/2²+1/3²)+√(1+1/3²+1/4²)+…+√(1+1/2003²+1/2004²)
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![化简√1+1/n²+(n+1)²得 [1+1/n²+(n+1)²]在根号内.计算:√(1+1/1²+1/2²)+√(1+1/2²+1/3²)+√(1+1/3²+1/4²)+…+√(1+1/2003²+1/2004²)](/uploads/image/z/6884655-15-5.jpg?t=%E5%8C%96%E7%AE%80%E2%88%9A1%2B1%2Fn%26%23178%3B%2B%28n%2B1%29%26%23178%3B%E5%BE%97+%5B1%2B1%2Fn%26%23178%3B%2B%28n%2B1%29%26%23178%3B%5D%E5%9C%A8%E6%A0%B9%E5%8F%B7%E5%86%85.%E8%AE%A1%E7%AE%97%EF%BC%9A%E2%88%9A%281%2B1%2F1%26%23178%3B%2B1%2F2%26%23178%3B%29%2B%E2%88%9A%281%2B1%2F2%26%23178%3B%2B1%2F3%26%23178%3B%29%2B%E2%88%9A%281%2B1%2F3%26%23178%3B%2B1%2F4%26%23178%3B%29%2B%E2%80%A6%2B%E2%88%9A%281%2B1%2F2003%26%23178%3B%2B1%2F2004%26%23178%3B%29)
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