想知道:y=(x 2)/(3x-1)4y=28,则y=7BE=BC CE=BC CA/2;CF=CA AF=CA AB/2f(x2)-f(x1)=loga(x2^2-ax2)-loga(x1^2-ax1)
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![想知道:y=(x 2)/(3x-1)4y=28,则y=7BE=BC CE=BC CA/2;CF=CA AF=CA AB/2f(x2)-f(x1)=loga(x2^2-ax2)-loga(x1^2-ax1)](/uploads/image/z/6885189-45-9.jpg?t=%E6%83%B3%E7%9F%A5%E9%81%93%EF%BC%9Ay%3D%28x+2%29%2F%283x-1%294y%3D28%2C%E5%88%99y%3D7BE%3DBC+CE%3DBC+CA%2F2%EF%BC%9BCF%3DCA+AF%3DCA+AB%2F2f%28x2%29-f%28x1%29%3Dloga%28x2%5E2-ax2%29-loga%28x1%5E2-ax1%29)
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想知道:y=(x 2)/(3x-1)4y=28,则y=7BE=BC CE=BC CA/2;CF=CA AF=CA AB/2f(x2)-f(x1)=loga(x2^2-ax2)-loga(x1^2-ax1)
想知道:y=(x 2)/(3x-1)4y=28,则y=7
BE=BC CE=BC CA/2;CF=CA AF=CA AB/2f(x2)-f(x1)=loga(x2^2-ax2)-loga(x1^2-ax1)
想知道:y=(x 2)/(3x-1)4y=28,则y=7BE=BC CE=BC CA/2;CF=CA AF=CA AB/2f(x2)-f(x1)=loga(x2^2-ax2)-loga(x1^2-ax1)
3(x-1)的平方-6=0x = (3√-5)3 = -5比如m2-2m 1-4m
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
x+y+2(-x-y+1)=3(1-y-x)-4-(y+x-1),x+y=?
化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1
先化简 再求值 (2x-y)(y+x)-(x-2y)(2y+x)-(-3y+x)^2其(√x+1)+y^2+4=-4y
已知x-y=1,求[(x+2y)^2+(2x+y)(x-4y)-3(x+y)(x-y)]除以y的值大神们帮帮忙
已知x-y=1,求[(x+2y)²+(2x+y)(x-4y)-3(x+y)(x-y)]÷y的值
(x-y) (x-2y)+(x+2y) (x-3y)-2(x-3y) (x-4y)=
[(y-2x)(-2x-y)+4(x-2y)平方]/3y,其中x=1,y=-3
[(2x+y)^2+(y+2x)(y-2x)-2y(4x-y)]/4y,其中x=1/2,y=1/3
x²/xy-x/y 3x/4x+y - x-2y/4x+y (1-y/y+x)÷x/y²-x²
先化简,再求值:[(x+y)(x-y)-(x-y)^2+2y(x-3y)]/(-4y),其中x=1,y=-2
9y=3x-(x-1),4(x+y)-(2x+4)=8y
为什么(x-2y)(x+4y)-(x-2y)+3(x+4y)-3=(x-2y+3)(x+4y-1).
解二元一次方程组:3(x+y)-4(x-y)=4,x+y/2+x-y/6+1x+y/2+x-y/6+1=1
4x(x-y)-(2x-3y)(2x-3y) x=1 y=-1
若x=-1/4,能否确定代数式(2x-y)(2x+y)+(2x-y)(y-4x)+2y(y-3x)的值?
若x+y=4,则多项式1/2(x+y)+4(x-y)-3(x-y)-3/2(x+y)-x+y值是()
先化简,再求值[2x的平方-(x+y)(y-x)][3(-x-y)(y-x)+4y的平方]其中x=三分之一y=1