作业帮导数计算问题lim x趋向无穷[(x-3)(2x^2+1)]/(2-7x^3)lim x趋向4 [e^x+cos(4-x)]/[(根号x)-3]
来源：学生作业帮助网 编辑：作业帮 时间：2024/08/01 06:04:46
![导数计算问题lim x趋向无穷[(x-3)(2x^2+1)]/(2-7x^3)lim x趋向4 [e^x+cos(4-x)]/[(根号x)-3]](/uploads/image/z/6891256-64-6.jpg?t=%E5%AF%BC%E6%95%B0%E8%AE%A1%E7%AE%97%E9%97%AE%E9%A2%98lim+x%E8%B6%8B%E5%90%91%E6%97%A0%E7%A9%B7%5B%28x-3%29%282x%5E2%2B1%29%5D%2F%282-7x%5E3%29lim+x%E8%B6%8B%E5%90%914+%5Be%5Ex%2Bcos%284-x%29%5D%2F%5B%28%E6%A0%B9%E5%8F%B7x%29-3%5D)
x){~ϳ^[|\4#'3WŶ&>ƚFqFچFqƚH
MS*5Lt+j5-{qMR>Dۆv6t P5 G 4Y%HH!H ^fچ@ E@ Z H_57Gv&a/jƙ r @!]C<;hڀ9t3dGӶ{zs=b۞dwݽH P
导数计算问题lim x趋向无穷[(x-3)(2x^2+1)]/(2-7x^3)lim x趋向4 [e^x+cos(4-x)]/[(根号x)-3]
导数计算问题
lim x趋向无穷[(x-3)(2x^2+1)]/(2-7x^3)
lim x趋向4 [e^x+cos(4-x)]/[(根号x)-3]
导数计算问题lim x趋向无穷[(x-3)(2x^2+1)]/(2-7x^3)lim x趋向4 [e^x+cos(4-x)]/[(根号x)-3]
lim(x->∞) [(x-3)(2x^2+1)]/(2-7x^3)
=lim(x->∞) (2x^3-6x^2+x-3)/(2-7x^3)
=lim(x->∞) (2-6/x+1/x^2-3/x^3)/(2/x^3-7)
=2/(-7)
=-2/7
lim(x->4) [e^x+cos(4-x)]/[(根号x)-3]
=(e^4+1)/(2-3)
=-e^4-1
看看高数上册，上面有详细地介绍