证明:[tan(x+y)-tanx]/1+tanxtan(x+y)=sin2x/2cosy^2
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/26 00:29:36
![证明:[tan(x+y)-tanx]/1+tanxtan(x+y)=sin2x/2cosy^2](/uploads/image/z/6896791-55-1.jpg?t=%E8%AF%81%E6%98%8E%EF%BC%9A%5Btan%28x%2By%29-tanx%5D%2F1%2Btanxtan%28x%2By%29%3Dsin2x%2F2cosy%5E2)
x){ٌ{fE$iThWj &h[gTo_\gdTON;Jl}}ً};m*t+4AJTfPS%HX_DdT>HE!M$Ae<Ɏ9@tj= %
证明:[tan(x+y)-tanx]/1+tanxtan(x+y)=sin2x/2cosy^2
证明:[tan(x+y)-tanx]/1+tanxtan(x+y)=sin2x/2cosy^2
证明:[tan(x+y)-tanx]/1+tanxtan(x+y)=sin2x/2cosy^2
左边=tan(x+y-x)=tany
右边=2sinycosy/2cos^2y
=siny/cosy
=tany
左边=右边
[tan(x+y)-tanx]/1+tanxtan(x+y)=sin2y/2cosy^2
啥东东啊?