y=cos(x+π/2)+sin(π/3-x)的最大值是...答案是根号3 急 明天开学

已知sinx=3/5,x∈(π/2,π),求【sin(x+y)+sin(x-y)】/【cos（x+y）+cos（x-y）】的值 1.y=sin(-X+π/6)2.y=cos(-2X+π/3) cos(x-y/2)=-1/9,sin(x/2-y)=2/3,π/2 y=2cos(x/4+ π/3)-3sin(x- π/4)y=sin(4x- π/3)-cos(3x+π/2) Sin x-sin y=2/3 cos x-cos y=1/2 求cos(x-y) 化简y=sin^2(x)+2sin(x)cos(x)+3cos^2(x) y=cosπx*cos(πx-π/3)+sin^2πx的周期、单调区间、值域 函数y=sin(2x+α)cos(x+α)-cos(2x+α)sin(x+α)在x=π/3处的导函数为 y =(cos^2) x - sin (3^x),求y' 函数Y=sin(2x+π/3)cos(x-π/6)-cos(2x+π/3)sin(x-π/6)的图像的一条对称轴方程是多少 求函数y=cos(9/2π+x)+sin^2x的最大值和最小值还有一题 已知sinx+cosx=1/2,求sin^3x+cos^3x和sin^4x+cos^2x y=cos(3/π+2x)sin(3/π-2x)的单调增区间 函数y=cos^2(3x+π/6)-sin^2(3x+π/6)化简 y=sin(2x-π/4)+cos(3x+π/3)的导数 求y=sin(2x+π/3)+cos(2x-π/6)的单调区间 函数y=cos(2x+3π)·sin(2x-π)的周期为 y=sin(2x-π/6)-3cos(2x-π/6)的值域 函数y=cos(x+π/2）+sin（π/3-x)化简