简便运算:1+1/1+2+1/1+2+3+……1/1+2+3+4+5+6+7+8+9+10 (请写出解答过程,OK?)还有一道简便运算题,恳请各位大师帮忙解答:1/2+1/4+1/6+1/8+1/10+1/12=?(也请写出解答过程,OK?)第一题我写的有些模糊,现
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/11 21:22:17
![简便运算:1+1/1+2+1/1+2+3+……1/1+2+3+4+5+6+7+8+9+10 (请写出解答过程,OK?)还有一道简便运算题,恳请各位大师帮忙解答:1/2+1/4+1/6+1/8+1/10+1/12=?(也请写出解答过程,OK?)第一题我写的有些模糊,现](/uploads/image/z/6905959-7-9.jpg?t=%E7%AE%80%E4%BE%BF%E8%BF%90%E7%AE%97%EF%BC%9A1%2B1%2F1%2B2%2B1%2F1%2B2%2B3%2B%E2%80%A6%E2%80%A61%2F1%2B2%2B3%2B4%2B5%2B6%2B7%2B8%2B9%2B10+%EF%BC%88%E8%AF%B7%E5%86%99%E5%87%BA%E8%A7%A3%E7%AD%94%E8%BF%87%E7%A8%8B%2COK%3F%EF%BC%89%E8%BF%98%E6%9C%89%E4%B8%80%E9%81%93%E7%AE%80%E4%BE%BF%E8%BF%90%E7%AE%97%E9%A2%98%2C%E6%81%B3%E8%AF%B7%E5%90%84%E4%BD%8D%E5%A4%A7%E5%B8%88%E5%B8%AE%E5%BF%99%E8%A7%A3%E7%AD%94%EF%BC%9A1%2F2%2B1%2F4%2B1%2F6%2B1%2F8%2B1%2F10%2B1%2F12%3D%3F%EF%BC%88%E4%B9%9F%E8%AF%B7%E5%86%99%E5%87%BA%E8%A7%A3%E7%AD%94%E8%BF%87%E7%A8%8B%2COK%3F%EF%BC%89%E7%AC%AC%E4%B8%80%E9%A2%98%E6%88%91%E5%86%99%E7%9A%84%E6%9C%89%E4%BA%9B%E6%A8%A1%E7%B3%8A%EF%BC%8C%E7%8E%B0)
简便运算:1+1/1+2+1/1+2+3+……1/1+2+3+4+5+6+7+8+9+10 (请写出解答过程,OK?)还有一道简便运算题,恳请各位大师帮忙解答:1/2+1/4+1/6+1/8+1/10+1/12=?(也请写出解答过程,OK?)第一题我写的有些模糊,现
简便运算:1+1/1+2+1/1+2+3+……1/1+2+3+4+5+6+7+8+9+10 (请写出解答过程,OK?)
还有一道简便运算题,恳请各位大师帮忙解答:
1/2+1/4+1/6+1/8+1/10+1/12=?
(也请写出解答过程,OK?)
第一题我写的有些模糊,现将题目写清楚一些:
1+(1/1+2)+(1/1+2+3)+……+(1/1+2+3······+10 )
简便运算:1+1/1+2+1/1+2+3+……1/1+2+3+4+5+6+7+8+9+10 (请写出解答过程,OK?)还有一道简便运算题,恳请各位大师帮忙解答:1/2+1/4+1/6+1/8+1/10+1/12=?(也请写出解答过程,OK?)第一题我写的有些模糊,现
原式=1+1/3+1/6+1/10+.+1/45+1/55
=2(1/2+1/6+1/12+1/20+.+1/90+1/110)
=2(1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+.+1/9-1/10+1/10-1/11)
=2(1-1/11)
=20/11
原式=1/2+1/6+1/12+1/4+1/8+1/10
=1-1/2+1/2-1/3+1/3-1/4+1/4+1/8+1/10
=1+ 1/8+1/10
= 49/40
原式=1+1/3+1/6+1/10+。。。+1/45+1/55
=2(1/2+1/6+1/12+1/20+。。。。。+1/90+1/110)
=2(1-1/2+1/2-1/3+1/3+1/4+1/4-1/5+。。。。+1/9-1/10+1/10-1/11)
=2(1-1/11)
=20/11
第二个自己算太简单了
第一题目在这里编辑的有一点错误,但是看懂了
因为 1+2+3+···+n=n(n+1)/2
所以题中第n项为 2/n(n+1)=2(1/n-1/n+1)
即原式=2(1/1-1/1+1+1/2-1/2+1+···+1/10-1/10+1)
=2(1-1/11)
...
全部展开
第一题目在这里编辑的有一点错误,但是看懂了
因为 1+2+3+···+n=n(n+1)/2
所以题中第n项为 2/n(n+1)=2(1/n-1/n+1)
即原式=2(1/1-1/1+1+1/2-1/2+1+···+1/10-1/10+1)
=2(1-1/11)
=20/11
第二题的规律是第n项为1/2n 解题想一想就能自己解的
收起