若5x²y+(2a-3)xy+7是三次二项式,求3a²-a+1
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若5x²y+(2a-3)xy+7是三次二项式,求3a²-a+1
若5x²y+(2a-3)xy+7是三次二项式,求3a²-a+1
若5x²y+(2a-3)xy+7是三次二项式,求3a²-a+1
2a-3=0
a=3/2
3a²-a+1
=3x(3/2)²-3/2+1
=27/4-1/2
=25/4
既然是三次二项式,那么(2a-3)xy=0,
即2a-3=0 a=3/2
把a=3/2代入式中就行