若(x+y-5)²+丨x-3y-17丨=0,求x-y的值
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若(x+y-5)²+丨x-3y-17丨=0,求x-y的值
若(x+y-5)²+丨x-3y-17丨=0,求x-y的值
若(x+y-5)²+丨x-3y-17丨=0,求x-y的值
两个非负数之和为0,两者只能同时为0时相加的和才可能为0.
(x+y-5)²+丨x-3y-17丨=0
(x+y-5)²>=0,丨x-3y-17丨>=0
(x+y-5)²=丨x-3y-17丨=0
x+y-5=0,x-3y-17=0
解得:x=8,y=-3
x-y=11
x+y=5,x-3y=17,解的x=8 y=-3 x-y=11