求用矩阵解三元方程x+y-z=3-z+y+2x=42y+z+2x-12=0suppose inverse of the L.H.S coefficient matrix,A^(-1),is -1 1 0 1.333 -1 0.333-0.667 0 0.333using inverse matrix method,find the solutions for the above simultaneous equations.
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求用矩阵解三元方程x+y-z=3-z+y+2x=42y+z+2x-12=0suppose inverse of the L.H.S coefficient matrix,A^(-1),is -1 1 0 1.333 -1 0.333-0.667 0 0.333using inverse matrix method,find the solutions for the above simultaneous equations.
求用矩阵解三元方程
x+y-z=3
-z+y+2x=4
2y+z+2x-12=0
suppose inverse of the L.H.S coefficient matrix,A^(-1),is -1 1 0
1.333 -1 0.333
-0.667 0 0.333
using inverse matrix method,find the solutions for the above simultaneous equations.
求用矩阵解三元方程x+y-z=3-z+y+2x=42y+z+2x-12=0suppose inverse of the L.H.S coefficient matrix,A^(-1),is -1 1 0 1.333 -1 0.333-0.667 0 0.333using inverse matrix method,find the solutions for the above simultaneous equations.
这个题很简单啊,上面的三元方程组看成Ax=b
A是系数矩阵,b=(3,4,12)T
Ax=b两边左乘A^(-1)
x=A^(-1)b
=|-1 1 0|
|4/3 -1 1/3| * (3,4 ,12)T
|-2/3 0 1/3|
=(1,4,2)T
所以x=1,y=4.z=2
第这个题目可以交给计算机来处理
计算机会很快处理的
你去华军软件园 下载个 软件来做
A= 1 1 -1
2 1 -1
2 2 1
B=[3,4,12]^T
X=[x,y,z]^T
原方程组用矩阵形式表示为
AX=B
则
X=A^(-1)B
=-1 1 0
1.333 -1 0.333 * [3,4,12]^T
-0.667 0 0.333
=[1,4,2]^T
故
x=1
y=4
z=2